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NEW QUESTION: 1
会社にはMicrosoft Office 365サブスクリプションがあります。
同社はMicrosoft Teamsを使用しています。
チームで使用できるのはMicrosoftアプリのみであることを確認する必要があります。
Microsoft Teamsの設定ページから何をすべきですか？
A. デフォルトで新しい外部アプリを有効にするをオフにします
B. Microsoft Teamsで外部アプリを許可をオフにします
C. デフォルトのアプリを無効にします
D. 外部アプリのサイドローディングを許可をオフにします
Answer: B

NEW QUESTION: 2
Which statement is true about the IKM SQL Control Append that creates an intermediate integration table prefixed with I$? (Choose the best answer.)
A. Theintermediate integration table prefixed with I$ is createdbecause the flow control is mandatory when doing an initial load.
B. Theintermediate integration table prefixed with I$is required to determine which records must be inserted.
C. IfFlow Control is not necessary, an I$ table is not created.
D. Neither the LKM northe IKM create intermediate tables. Most of their work is performed in the ODI Agent memory.
Answer: D
Explanation:
(http://www.oracle.com/us/products/middleware/data-integration/odi-performanceguide-wp-2147067.pdf)

NEW QUESTION: 3
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server.
The database contains two tables that have the following definitions:

Global customers place orders from several countries.
You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. ShippingCountry) cs
WHERE Rnk = 1
B. ShippingCountry) cs
WHERE Rnk = 1
C. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
Where o.Rnk = 1
D. ShippingCountry,
RANK() OVER (PARTITION BY c. CustomerID
ORDER BY o. OrderAmount DESC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName,
E. SELECT CustomerID, CustomerName, ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK() OVER (PARTITION BY c.CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName,
F. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
G. SELECT CustomerID, CustomerName, ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName,
Answer: F

NEW QUESTION: 4

A. %symdel Mv_Info;
B. %mdelete & Mv_Info;
C. %symercase Mv_Info;
D. %symdel & Mv_Info;
Answer: A

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• EXIN EPI Data Centre
• EXIN Certified Entry Networking Technician