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NEW QUESTION: 1
A systems administrator receives a notification from the RAID controller that the RAID 5 array is degraded. Upon logging into the server, the administrator sees that on local disk 0, physical disk 2 has failed. Which of the following is the BEST course of action to take to resolve the problem?
A. In the controller, convert the RAID 5 array to RAID 0 array to avoid system downtime. Wait until the array is rebuilt and confirm in the RAID controller that the system is no longer degraded.
B. Delete logical disk 0 and manually configure a new RAID array only using the known-good working drives. Wait until the array is rebuilt and confirm in the RAID controller that the system is no longer degraded.
C. Immediately replace physical disk 2. Wait until the arrays is rebuilt and confirm in the RAID controller that the system is no longer degraded.
D. Schedule system downtime and replace physical disk 2. Wait until the array is rebuilt and confirm in the RAID controller that the system is no longer degraded.
Answer: D

NEW QUESTION: 2
An administrator is working with the 192.168.4.0 network, which has been subnetted with a /26 mask. Which two addresses can be assigned to hosts within the same subnet? (Choose two.)
A. 192.168.4.63
B. 192.168.4.132
C. 192.168.4.61
D. 192.168.4.128
E. 192.168.4.67
F. 192.168.4.125
Answer: E,F
Explanation:
Explanation
Increment: 64 (/26 = 11111111.11111111.11111111.1
The IP 192.168.4.0 belongs to class C.
The default subnet mask of class C is /24 and it has been subnetted with a /26 mask so we have 2(26-24) = 22 = 4 sub-networks:
1st subnet: 192.168.4.0 (to 192.168.4.63)
2nd subnet: 192.168.4.64 (to 192.168.4.127)
3rd subnet: 192.168.4.128 (to 192.168.4.191)
4th subnet: 192.168.4.192 (to 192.168.4.225)
In all the answers above, only answer C and D are in the same subnet.
Therefore only IPs in this range can be assigned to hosts.

NEW QUESTION: 3
Peter extracts the SIDs list from Windows 2000 Server machine using the hacking tool "SIDExtractor". Here is the output of the SIDs:
s-1-5-21-1125394485-807628933-54978560-100Johns s-1-5-21-1125394485-807628933-54978560-652Rebecca s-1-5-21-1125394485-807628933-54978560-412Sheela s-1-5-21-1125394485-807628933-54978560-999Shawn s-1-5-21-1125394485-807628933-54978560-777Somia s-1-5-21-1125394485-807628933-54978560-500chang s-1-5-21-1125394485-807628933-54978560-555Micah
From the above list identify the user account with System Administrator privileges.
A. Micah
B. Somia
C. Chang
D. Rebecca
E. John
F. Sheela
G. Shawn
Answer: C
Explanation:
The SID of the built-in administrator will always follow this example: S-1-5-domain

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