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NEW QUESTION: 1
会社にはMicrosoft Office 365サブスクリプションがあります。
同社はMicrosoft Teamsを使用しています。
チームで使用できるのはMicrosoftアプリのみであることを確認する必要があります。
Microsoft Teamsの設定ページから何をすべきですか？
A. デフォルトで新しい外部アプリを有効にするをオフにします
B. 外部アプリのサイドローディングを許可をオフにします
C. Microsoft Teamsで外部アプリを許可をオフにします
D. デフォルトのアプリを無効にします
Answer: C

NEW QUESTION: 2
Which statement is true about the IKM SQL Control Append that creates an intermediate integration table prefixed with I$? (Choose the best answer.)
A. Theintermediate integration table prefixed with I$is required to determine which records must be inserted.
B. Neither the LKM northe IKM create intermediate tables. Most of their work is performed in the ODI Agent memory.
C. IfFlow Control is not necessary, an I$ table is not created.
D. Theintermediate integration table prefixed with I$ is createdbecause the flow control is mandatory when doing an initial load.
Answer: B
Explanation:
(http://www.oracle.com/us/products/middleware/data-integration/odi-performanceguide-wp-2147067.pdf)

NEW QUESTION: 3
You are a database developer for an application hosted on a Microsoft SQL Server 2012 server.
The database contains two tables that have the following definitions:

Global customers place orders from several countries.
You need to view the country from which each customer has placed the most orders.
Which Transact-SQL query do you use?
A. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
COUNT(OrderAmount) AS OrderAmount
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
ORDER BY OrderAmount DESC
B. ShippingCountry) cs
WHERE Rnk = 1
C. ShippingCountry) cs
WHERE Rnk = 1
D. SELECT CustomerID, CustomerName, ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName, o.ShippingCountry,
RANK() OVER (PARTITION BY c.CustomerID
ORDER BY COUNT(o.OrderAmount) ASC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName,
E. ShippingCountry,
RANK() OVER (PARTITION BY c. CustomerID
ORDER BY o. OrderAmount DESC) AS Rnk
FROM Customer c
INNER JOIN Orders o
ON c.CustomerID = o.CustomerID
GROUP BY c.CustomerID, c.CustomerName,
F. SELECT c.CustomerID, c.CustomerName, o.ShippingCountry
FROM Customer c
INNER JOIN
(SELECT CustomerID, ShippingCountry,
RANK() OVER (PARTITION BY CustomerID
ORDER BY COUNT(OrderAmount) DESC) AS Rnk
FROM Orders
GROUP BY CustomerID, ShippingCountry) AS o
ON c.CustomerID = o.CustomerID
Where o.Rnk = 1
G. SELECT CustomerID, CustomerName, ShippingCountry
FROM
(SELECT c.CustomerID, c.CustomerName,
Answer: A

NEW QUESTION: 4

A. %symercase Mv_Info;
B. %symdel Mv_Info;
C. %mdelete & Mv_Info;
D. %symdel & Mv_Info;
Answer: B

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