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NEW QUESTION: 1
Note This question is part of a series of questions that use the same scenario.
For your convenience, the scenario is repeated in each question.
Each question presents a different goal and answer choices, but the text of the scenario is exactly the same in each question in this series.
Start of Repeated Scenario:
Your network contains an Active Directory domain named contoso.com.
The functional level of the forest and the domain is Windows Server 2008 R2 All servers in the domain run
Windows Server 2016 Standard. The domain contains 300 client computers that run either
Windows 8.1 or Windows 10.
The domain contains nine servers that are configured as shown in the following table.

The virtual machines are configured as follows:
* E ach virtual machine has one virtual network adapter
* VM1 and VM2 are part of a Network Load Balancing (NIB) cluster.
* All of the servers on the network can communicate with all of the virtual machines.
End of repeated Scenario.
On server4, you plan to provision a new volume that will be used to create large, fixed-size VHDX files.
Which type of file system should you use the new volume to minimize the amount of time required to create the VHDX files?
A. ReFS
B. NTFS
C. CVFS
D. exFAT
Answer: A

NEW QUESTION: 2
Which of the following statements is related with the first law of OPSEC?
A. If you are not protecting it (the critical and sensitive information), the adversary wins!
B. If you don't know about your security resources you could not protect your network.
C. If you don't know what to protect, how do you know you are protecting it?
D. If you don't know the threat, how do you know what to protect?
Answer: D

NEW QUESTION: 3
質問をドラッグアンドドロップ
IPv4ネットワークサブネットを左側から右側の正しい使用可能なホスト範囲にドラッグアンドドロップします

Answer:
Explanation:

Explanation:
This subnet question requires us to grasp how to subnet very well. To quickly find out the subnet range, we have to find out the increment and the network address of each subnet. Let's take an example with the subnet 172.28.228.144/18:
From the /18 (= 1100 0000 in the 3rd octet), we find out the increment is 64. Therefore the network address of this subnet must be the greatest multiple of the increment but not greater than the value in the 3rd octet (228). We can find out the 3rd octet of the network address is 192 (because 192 = 64 * 3 and 192 < 228) -> The network address is 172.28.192.0. So the first usable host should be 172.28.192.1 and it matches with the 5th answer on the right. In this case we don't need to calculate the broadcast address because we found the correct answer.
Let's take another example with subnet 172.28.228.144/23 -> The increment is 2 (as /23 = 1111
1110 in 3rd octet) -> The 3rd octet of the network address is 228 (because 228 is the multiply of 2 and equal to the 3rd octet) -> The network address is 172.28.228.0 -> The first usable host is
172.28.228.1. It is not necessary but if we want to find out the broadcast address of this subnet, we can find out the next network address, which is 172.28.(228 + the increment number).0 or
172.28.230.0 then reduce 1 bit -> 172.28.229.255 is the broadcast address of our subnet.
Therefore the last usable host is 172.28.229.254.

NEW QUESTION: 4



A. context.content.rotate (90);
B. context.rotate(90);
C. context.transform(90);
D. context.content.getRotation(90);
Answer: B
Explanation:
The rotate() method rotates the current drawing.
Example
Rotate the rectangle 20 degrees:
JavaScript:
var c=document.getElementById("myCanvas");
var ctx=c.getContext("2d");
ctx.rotate(20*Math.PI/180);
ctx.fillRect(50,20,100,50);
Reference: HTML canvas rotate() Method

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