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NEW QUESTION: 1
A data engineer needs to architect a data warehouse for an online retail company to store historic purchases. The data engineer needs to use Amazon Redshift. To comply with PCI:DSS and meet corporate data protection standards, the data engineer must ensure that data is encrypted at rest and that the keys are managed by a corporate on-premises HSM.
Which approach meets these requirements in the most cost-effective manner?
A. Use the AWS CloudHSM service to establish a trust relationship between the CloudHSM and the corporate HSM over a Direct Connect connection. Configure Amazon Redshift to use the CloudHSM device.
B. Configure the AWS Key Management Service to point to the corporate HSM device, and then launch the Amazon Redshift cluster with the KMS managing the encryption keys.
C. Use AWS Import/Export to import the corporate HSM device into the AWS Region where the Amazon Redshift cluster will launch, and configure Redshift to use the imported HSM.
D. Create a VPC, and then establish a VPN connection between the VPC and the on-premises network. Launch the Amazon Redshift cluster in the VPC, and configure it to use your corporate HSM.
Answer: D
Explanation:
Amazon Redshift can use an on-premises HSM for key management over the VPN, which ensures that the encryption keys are locally managed. Option B is possible: CloudHSM can cluster to an on-premises HSM.
that doesn't
But then key management could be performed on either the on-premises HSM or CloudHSM, and meet the design goal. Option C does not describe a valid feature of KMS and violates the requirement for the corporate HSM to manage the keys requirement, even if it were possible.
Option D is not possible because you cannot put hardware into an AWS Region.

NEW QUESTION: 2
You have a file server named Server1 that runs Windows Server 2012 R2. Data Deduplication is enabled on drive D of Server1.
You need to exclude D:\Folder1 from Data Deduplication.
What should you configure?
A. File and Storage Services in Server Manager
B. The classification rules in File Server Resource Manager (FSRM)
C. The properties of D:\Folder1
D. Disk Management in Computer Management
Answer: A

NEW QUESTION: 3
The probability that events A and B do not occur simultaneously equals 0.77. The probability of neither A nor B occurring equals 0.38. If P(A) equals 0.26, the probability of B occurring equals ________.
A. 0.59
B. 0.43
C. 0.62
D. 0.21
Answer: A
Explanation:
Explanation/Reference:
Explanation:
The probability that events A and B do not occur simultaneously equals one minus the probability that events A and B occur simultaneously. Thus, P(A and B) = 1 - 0.77 = 0.23.
The probability of neither A nor B occurring equals one minus the probability of either A or B occurring.
Thus, P(A or B) = 1 - 0.38 = 0.62.
Now, P(A or B) = P(A) + P(B) - P(A and B). Therefore, P(B) = P(A or B) - P(A) + P(A and B) = 0.62 - 0.26 +
0.23 = 0.59.

NEW QUESTION: 4
How is confidentiality defined in the CVSS v3.0 framework?
A. confidentiality of the information resources managed by a person due to a successfully exploited vulnerability
B. confidentiality of the information resources managed by a person due to an unsuccessfully exploited vulnerability.
C. confidentiality of the information resources managed by a software component due to a successfully exploited vulnerability.
D. confidentiality of the information resources managed by a software component due to an unsuccessfully exploited vulnerability
Answer: C
Explanation:
Explanation/Reference:
Reference: https://www.first.org/cvss/specification-document

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