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NEW QUESTION: 1
A network administrator is assigned to run and connect a Cat 6e Ethernet cable between two nodes in a
datacenter. Which of the following connector types should the network administrator use to terminate this
cable?
A. DB-9
B. RJ-45
C. DB-25
D. RS-232
Answer: B

NEW QUESTION: 2
DRAG DROP
You are developing a SQL Server Analysis Services (SSAS) cube.
You need to reuse a measure group from a different database.
In SQL Server Data Tools (SSDT), which three actions should you perform in sequence? (To answer, move the appropriate actions from the list of actions to the answer area and arrange them in the correct order.)

Answer:
Explanation:

NEW QUESTION: 3
カウント関数に関して正しい2つのステートメントはどれですか。
A. カウント（cust_id）は、重複する顧客IDとCUST_ID列のNULL値を持つ行を含む行数を返します。
B. カウント（個別のinv_amt）は、INV_AMT列に重複およびNULL値を含む行を除く行数を返します。
C. カウント（*）は、重複する行およびいずれかの列にnull値を含む行を含む行の数を返します。
D. count関数は、CHAR、VARCHAR2、およびNUMBERデータ型にのみ使用できます。
E. DISTINCTキーワードを指定したCOUNT関数を使用するselectステートメントにwhere句を含めることはできません。
Answer: B,C
Explanation:
Using the COUNT Function
The COUNT function has three formats:
COUNT(*)
COUNT(expr)
COUNT(DISTINCT expr)
COUNT(*) returns the number of rows in a table that satisfy the criteria of the SELECT statement, including duplicate rows and rows containing null values in any of the columns.
If a WHERE clause is included in the SELECT statement, COUNT(*) returns the number of rows that satisfy the condition in the WHERE clause.
In contrast,
COUNT(expr) returns the number of non-null values that are in the column identified by expr.
COUNT(DISTINCT expr) returns the number of unique, non-null values that are in the column identified by expr.

NEW QUESTION: 4
STUDENTSテーブルの構造を調べます。

INT SQLコースで最高のランキングを達成し、1999年にコースを修了した10人の学生のレポートを作成する必要があります。
このタスクを実行するSQLステートメントはどれですか。
A. SELECT。 student_id、marks、ROWNUM "Rank"。から。 （SELECT student_id、marks。
から。学生。 WHERE（finish_date BETWEEN '01 -JAN-99 AND '31 -DEC-99 '。AND course_id =' INT_SQL '。ORDER BY marks DESC）どこ 。 ROWNUM <= 10;。
B. SELECT。 student_id、marks、ROWNUM "Rank"。から。 （SELECT student_id、marks。
から。学生。どこ 。 ROWNUM <= 10. AND。 finish_date BETWEEN '01 -JAN-99 'AND '31 -DEC-。 99分。そして。コースID = 'INT_SQL'。 ORDER BY。マークDESC）;
C. SELECT。 student_id、marks、ROWID「ランク」。から。学生。どこ 。 ROWID <
10。かつ。 finish_date BETWEEN '01 -JAN-99 'AND '31 -DEC-99'。そして。コースID
'INT_SQL'。 ORDER BY。マーク;
D. SELECT。学生ID、マーク、ROWNUM「ランク」。から。 （SELECT student_id、marks。
学生から。 ORDER BYマーク）。どこ。 ROWNUM <= 10. AND。終了日
'01 -JAN-99 'と'31 -DEC-99'の間。そして。コースID = 'INT_SQL';
E. SELECT。 student_ id、marks、ROWNUM "Rank" FROM。学生WHERE。 ROWNUM
<= 10AND。 finish_date BETWEEN '01 -JAN-99 'AND '31 -DEC-99AND。コースID
'INT_SQL'ORDER BY。 DESCをマークします。
Answer: A

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