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NEW QUESTION: 1
Which four techniques can you use for IP data plane security? (Choose four.)
A. Control Plane Policing
B. QoS
C. MD5 authentication
D. uRPF
E. interface ACLs
F. FPM
Answer: B,D,E,F
Explanation:
Determining Where and When to Configure Access Lists To provide the security benefits of ACLs, at a minimum an ACL should be configured on the border routers, which are routers situated at the edges of the network. This setup provides a basic buffer from the outside network or from a less-controlled area of the network into a more sensitive area of the network. An ACL can be configured so that inbound traffic or outbound traffic, or both, are filtered on an interface. ACLs should be defined on a per-protocol basis. In other words, an ACL should be defined for every protocol enabled on an interface if that protocols traffic is to be controlled.
Unicast Reverse Path Forwarding (Unicast RPF) On modern networks, one of the most common attack types involves the forging or spoofing of IP source addresses. The configuration of ACLs for this purpose on large networks can be very cumbersome and hard to maintain. In an attempt to develop a technology to deal with these issues, Unicast Reverse Path Forwarding (URPF) was developed. Unicast RPF provides a source validation step to packet handling; it does this by verifying the source information of a packet to information contained within the Cisco Express Forwarding (CEF) Forwarding Information Base (FIB). The CEF FIB is a table that contains packet-switching information that mirrors that of the routing table; this is used by the device to increase the speed of packets being forwarding through the device. Because Unicast RPF relies on CEF's FIB, CEF must be configured on the device before Unicast RPF is configured Flexible Packet Matching Flexible Packet Matching (FPM) was created to be a more thorough and customized packet filter option. FPM enables the user to configure match parameters based on arbitrary bits of a packet and arbitrary depths within the packet header and payload. This technique can be used to mitigate several different types of attack, including slow-path denial of service and zero-day virus and malware. FPM is implemented using a filtering policy that is divided into four tasks:
Loading of a Protocol Header Description File (PHDF)
Defining a class map and a specific protocol stack chain (traffic class)
Defining a service policy (traffic policy)
Application of a service policy on a specific interface
----
Reference: http://www.ciscopress.com/articles/article.asp?p=1716288&seqNum=2

NEW QUESTION: 2
You have a server named Server1 that runs Windows Server 2016. Server1 has the Web Application Proxy role service installed.
You are publishing an application named App1 that will use Integrated Windows authentication as shown in the following graphic.

Use the drop-down menus to select the answer area choice that completes each statement based on the information presented in the graphic.

Answer:
Explanation:

Explanation

NEW QUESTION: 3
Drag and drop the characteristics from the left onto the routing protocols they describe on the right.

Answer:
Explanation:

Explanation:
EIGRP maintains alternative loop-free backup via the feasible successors. To qualify as a feasible successor, a router must have an Advertised Distance (AD) less than the Feasible distance (FD) of the current successor route.
Advertised distance (AD): the cost from the neighbor to the destination. Feasible distance (FD): The sum of the AD plus the cost between the local router and the next-hop router

NEW QUESTION: 4
What happens when you attempt to compile and run the following code?
# include <iostream>
# include <deque>
# include <list>
# include <queue>
# include <vector>
using namespace std;
int main()
{
deque<int> mydeck;list<int> mylist; vector<int> myvector;
queue<int> first; queue<int> second(mydeck);
queue<int> third(second); queue<int, list<int> > fourth(mylist);
fourth.push(10);fourth.push(11);fourth.push(12);
queue<int, vector<int> > fifth(myvector);
fifth.push(10);fifth.push(11);fifth.push(12); // Line I
while(!fifth.empty())
{
cout<<fifth.front()<<" "; // Line II
fifth.pop(); // Line III
}
while (!fourth.empty())
{
cout << fourth.front() << " ";
fourth.pop(); // Line IV
}
return 0;
}
A. program outputs: 10 11 12 10 11 12
B. compilation error in line III
C. compilation error in line II
D. compilation error in line IV
E. compilation error in line I
Answer: B

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