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NEW QUESTION: 1
A developer is writing an application with three java Persistence API entities: order, customer, and Address. There is a many-to-one relationship between order and customer, and a one to-many relationship between customer and Address.
Which two Criteria queries will return the orders of all customers who have an address whose value specified by the String parameter postalcode? (Choose two)
A. String postalCode = . . .
Criteria Builder cb = . . .
CriteriaQuery<order> cq = cb.createQuery (Order.class);
Root <order> order = cq.from(order.class);
Join <order, Customer> customer = order.join(Order_.customer);
Root <Order> order = cq.from (Order.class);
Join <customer, Address> address = customer join (Order_.customer)
cq.where (cb.equal (address.get(Address_.postalCode), postalCode));
cq.select (order). Distinct (true);
// query execution code here
. . .
B. String postalCode = ...
CriteriaBuilder cb = ...
Root<order> order = cq- from (Order . class ) ,
Join<order, Address> address = order . join (Order_. customer) -join (Customer_.addresses);
cq.where <cb.equal (address.get(Address_.postalCode) , postalCode) ) ;
cq.selec:(order).distinct(true);
// query execution code here
. . .
C. String postalCode = . . .
Criteria Builder cb = . . .
Root <Order> order = cq.from (Order.class);
order.join (order_. customer).join(Customer_.addresses);
cq.where (cb.equal (address.get(Address_.postalCode), postalCode));
cq.select (order). Distinct (true);
// query execution code here
D. String postalCode = ...
CritetiaBuilder cb = ...
Root<order> order = cq - from (Order . class) ,
Join<order, Address> address = order.join(Customer_.addresses);
cq.where(ct>.equal(address.get(Address_.postalCode), postalCode));
cq-select(order).distinct(true);
// query execution code here
. . .
Answer: B,D

NEW QUESTION: 2
You have a Hyper-V host named Server1 that runs Windows Server 2016 datacenter. Server1 is activated.
On Server1, you deploy a virtual machine named VM1 that has a Server Core installation of Windows Server
2016 Standard.
You need to activate VM1 by using Automatic Virtual Machine Activation (AVMA).
Which command should you run? To answer, select the appropriate options in the answer area.
NOTE: Each correct selection is worth one point.

Answer:
Explanation:

Explanation

References:
https://blogs.technet.microsoft.com/askcore/2013/11/13/activating-virtual-machines-via-automatic-virtual-machi

NEW QUESTION: 3
You are making a Windows software by employing Microsoft .Net Framework 4 and Microsoft Visual Studio 2010.The business logic layer of the software is applied by using Windows Communication Groundwork (WCF). You produce a WCF services that consists of a single operation to upload big binary information files. You configure the binding of the WCF support to allow information streaming. You need to guarantee that the WCF service operation gets binary info files along with a string parameter that contains the description of each file. You generate a service operation that gets a single parameter. What should you do following?
A. Put into action the service parameter as a MessageContract class that is made up of a MessageHeader property for the description of the file and a MessageBodyMember house for the material of the data file.
B. Implement the services parameter as a MessageContract class that is made up of a MessageBodyMember home for the description of the file and yet another MessageBodyMember house for the content of the info file.
C. Carry out the support parameter as a Serializable class that consists of a house for the description of the file and an additional residence for the content of the info file
D. Put into action the support parameter as a DataContract class that is made up of a DataMember house for the description of the file and yet another DataMember residence for the content material of the info file.
Answer: A

NEW QUESTION: 4
Ressourcenkalender sind enthalten in:
A. Projektcharta.
B. Projektkommunikationsplan.
C. Projektstrukturplan (PSP).
D. Personalmanagementplan.
Answer: D

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